Substitute the known value of the area, 161 cm², and the base length, 23 cm, into the formula, leaving the altitude denoted as h.

Multiply both sides by 2 to clear the fraction, giving 161 × 2 = 322. Then divide 322 by 23 to obtain h = 14 cm.

4- The base of a triangle is $23\text{ cm}$ long and its area is $161\text{ sq. cm}$ . Find the length of the altitude.

Answer: $14\text{ cm}$

Step-by-step solution

Step 1: State the formula for the area of a triangle

The area of any triangle is given by half the product of its base and its corresponding altitude (or height). Here, the base $b = 23\text{ cm}$ and the area $A = 161\text{ cm}^2$ .

Step 2: Substitute the given values into the formula

Substitute the known value of the area, $161\text{ cm}^2$ , and the base length, $23\text{ cm}$ , into the formula, leaving the altitude denoted as $h$ .

Step 3: Solve for the altitude

Multiply both sides by $2$ to clear the fraction, giving $161 \times 2 = 322$ . Then divide $322$ by $23$ to obtain $h = 14\text{ cm}$ .

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4- The base of a triangle is 23 cm23\text{ cm}23 cm long and its area is 161 sq. cm161\text{ sq. cm}161 sq. cm. Find the length of the altitude.

Step-by-step solution

Step 1: State the formula for the area of a triangle

Step 2: Substitute the given values into the formula

Step 3: Solve for the altitude

4- The base of a triangle is $23\text{ cm}$ long and its area is $161\text{ sq. cm}$ . Find the length of the altitude.