A bag holds 7/8​ kg of rice. If each small container holds ​ 1/6 kg of rice, how many full containers can be filled? how will we know which is numerator and denominator- in fractions a part of whole and denominator is whole right then why is opposite. why 7/8 is numerator but its total

Answer: 55 full containers can be filled (with 14\frac{1}{4} of a container remaining). 78\frac{7}{8} is in the numerator because it is the total quantity (dividend) being divided by the unit capacity (divisor 16\frac{1}{6}).

Step-by-step solution

Step 1: Distinguish single fractions from division of quantities

In a single fraction like 78\frac{7}{8}, the number 88 represents the whole divided into equal parts, and 77 represents the parts taken. However, when finding how many containers can be filled from a total amount, we are performing division across two different quantities. Just like dividing 20 kg20\text{ kg} by 4 kg4\text{ kg} gives 204\frac{20}{4}, the total amount available, 78 kg\frac{7}{8}\text{ kg}, is the dividend (the top or numerator of the overall division), and the container capacity, 16 kg\frac{1}{6}\text{ kg}, is the divisor (the denominator of the overall division).

Step 2: Set up the division expression

To determine how many groups of size 16 kg\frac{1}{6}\text{ kg} fit into the total of 78 kg\frac{7}{8}\text{ kg}, we divide the total rice by the capacity of one container. This forms a complex fraction where the dividend 78\frac{7}{8} is in the numerator of the division, and the divisor 16\frac{1}{6} is in the denominator.

Step 3: Multiply by the reciprocal of the divisor

Dividing by a fraction is equivalent to multiplying by its reciprocal. The reciprocal of 16\frac{1}{6} is 61\frac{6}{1}. Multiplying the numerators gives 7×6=427 \times 6 = 42, and multiplying the denominators gives 8×1=88 \times 1 = 8.

Step 4: Simplify and determine full containers

Dividing the numerator and denominator by their common factor 22 yields 214\frac{21}{4}. Converting this improper fraction to a mixed number gives 55 and 14\frac{1}{4}, which means 55 full containers can be filled, with 14\frac{1}{4} of a container left over.

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