In the right-angled triangle OMA, by Pythagoras theorem, OA² = OM² + AM². Solving for OM, we get OM = √(17² - 15²) = √64 = 8 cm.

A d is a diameter of a circle and a b is a chord if a d is equals to 34 CM ab is equals to 30 cm the distance of a b from the centre of the circle is dash

Answer: 8 cm

Step-by-step solution

Step 1: Find the radius of the circle

Let $O$ be the centre of the circle. The radius $r$ is half of the diameter $AD$ . Since $AD = 34\text{ cm}$ , the radius $OA = 17\text{ cm}$ .

Step 2: Determine the length of the bisected chord segment

Draw a perpendicular $OM$ from the centre $O$ to chord $AB$ . The perpendicular from the centre of a circle to a chord bisects the chord. Therefore, $AM = MB = \frac{30}{2} = 15\text{ cm}$ .

Step 3: Apply Pythagoras theorem to find the distance

In the right-angled triangle $\triangle OMA$ , by Pythagoras theorem, $OA^2 = OM^2 + AM^2$ . Solving for $OM$ , we get $OM = \sqrt{17^2 - 15^2} = \sqrt{64} = 8\text{ cm}$ .

Solve your own maths question free →