(a) If cos⁡θ=35\cos \theta = \frac{3}{5}, find the value of tan⁡θ+sin⁡θcosec θ−cot⁡θ\frac{\tan \theta + \sin \theta}{\text{cosec } \theta - \cot \theta}. OR (b) For θ=30∘\theta = 30^\circ, verify that cos⁡2θ=cos⁡2θ−sin⁡2θ\cos 2\theta = \cos^2 \theta - \sin^2 \theta.

Answer: 6415\frac{64}{15}

Step-by-step solution

Step 1: Calculate sin⁡θ\sin \theta and tan⁡θ\tan \theta

Given cos⁡θ=35\cos \theta = \frac{3}{5}, we can use the identity sin⁡2θ+cos⁡2θ=1\sin^2 \theta + \cos^2 \theta = 1 to find sin⁡θ\sin \theta. Once sin⁡θ\sin \theta is known, we can calculate tan⁡θ\tan \theta using the identity tan⁡θ=sin⁡θcos⁡θ\tan \theta = \frac{\sin \theta}{\cos \theta}.

Step 2: Calculate cosec θ\text{cosec } \theta and cot⁡θ\cot \theta

Next, we find the reciprocal trigonometric ratios. cosec θ\text{cosec } \theta is the reciprocal of sin⁡θ\sin \theta, and cot⁡θ\cot \theta is the reciprocal of tan⁡θ\tan \theta.

Step 3: Substitute values into the expression

Now we substitute the calculated values of sin⁡θ\sin \theta, tan⁡θ\tan \theta, cosec θ\text{cosec } \theta, and cot⁡θ\cot \theta into the given expression.

Step 4: Simplify the expression

We simplify the numerator and the denominator separately. The numerator becomes 20+1215=3215\frac{20+12}{15} = \frac{32}{15}, and the denominator becomes 24=12\frac{2}{4} = \frac{1}{2}. Finally, we divide the numerator by the denominator.

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