To fill (5)/(6) of the tank, we multiply the time taken for the whole tank by (5)/(6). Multiplying 3 by (5)/(6) simplifies to (5)/(2) min.

Converting the improper fraction (5)/(2) to a mixed number gives 2(1)/(2) min, which is equal to 2 min and 30 s.

A pipe can fill 1/3 of a tank in 1 min how long will it takt to fill 5/6 of the tank

Answer: $2\frac{1}{2}\text{ minutes}$ (or $2\text{ min } 30\text{ s}$ )

Step-by-step solution

Step 1: Find the time required to fill the entire tank

Since the pipe fills $\frac{1}{3}$ of the tank in $1\text{ min}$ , we find the time taken to fill the complete tank (which represents $1$ whole unit) by dividing $1$ by $\frac{1}{3}$ . This gives $3\text{ min}$ .

Step 2: Calculate the time to fill five-sixths of the tank

To fill $\frac{5}{6}$ of the tank, we multiply the time taken for the whole tank by $\frac{5}{6}$ . Multiplying $3$ by $\frac{5}{6}$ simplifies to $\frac{5}{2}\text{ min}$ .

Step 3: Convert into mixed fraction and seconds

Converting the improper fraction $\frac{5}{2}$ to a mixed number gives $2\frac{1}{2}\text{ min}$ , which is equal to $2\text{ min}$ and $30\text{ s}$ .

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