A radioactive substance decays according to the equation dN/dt = -kN. If the initial amount is N₀ and half-life is T, express N(t) in terms of N₀, T, and t.

Answer: N(t)=N02−t/TN(t) = N_0 2^{-t/T}

Step-by-step solution

Step 1: Solve the differential equation

The given differential equation describes the rate of decay of a radioactive substance. To solve for N(t)N(t), we separate the variables by moving all terms involving NN to one side and all terms involving tt to the other side.

Step 2: Integrate both sides

Integrating both sides of the separated equation yields the natural logarithm of NN on the left and −kt-kt plus an integration constant CC on the right. This is a standard integration step for this type of differential equation.

Step 3: Solve for N(t) using initial condition

We can rewrite the equation as N(t)=e−kt+CN(t) = e^{-kt+C}. Using the initial condition N(0)=N0N(0) = N_0, we find that N0=eCN_0 = e^C, so the constant eCe^C is equal to N0N_0. This gives us the general form of exponential decay.

Step 4: Use half-life to find k

The half-life TT is the time it takes for the substance to decay to half its initial amount. We substitute N(T)=N0/2N(T) = N_0/2 into the decay equation to solve for the decay constant kk in terms of TT.

Step 5: Substitute k back into N(t)

Finally, we substitute the expression for kk back into the equation for N(t)N(t). Using the logarithm property eln⁡(x)=xe^{\ln(x)} = x, we can simplify the expression to a more common form involving base 2.

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