(a) Show that the points (−3,3)( -3, 3), (3,−3)(3, -3) and (33,33)(3\sqrt{3}, 3\sqrt{3}) are the vertices of an equilateral triangle. OR (b) Prove that A(4, 3), B(6, 4), C(5, 6), D(3, 5) are the vertices of a square ABCD.

Answer: The points A(4, 3), B(6, 4), C(5, 6), D(3, 5) are the vertices of a square ABCD.

Step-by-step solution

Step 1: Calculate the lengths of the sides

To prove that the given points form a square, we first need to calculate the lengths of all four sides using the distance formula, which is (x2−x1)2+(y2−y1)2\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}. If all four sides are equal, it could be either a square or a rhombus.

Step 2: Calculate the lengths of the diagonals

Next, we calculate the lengths of the diagonals ACAC and BDBD using the same distance formula. If the diagonals are also equal in length, then the figure is a square. If the diagonals were not equal, it would be a rhombus.

Step 3: Conclusion

Since all four sides are equal (AB=BC=CD=DA=5AB = BC = CD = DA = \sqrt{5}) and both diagonals are equal (AC=BD=10AC = BD = \sqrt{10}), the quadrilateral ABCDABCD is a square.

More from this chapter

All Coordinate Geometry solutions →

Solve your own maths question free →