We are given that the number of dolls is d = 6. Substituting 6 in place of d, we calculate 3 × 6 = 18, and subtracting 4 gives 14 teddy bears in the first store.

A toy store has 4 fewer teddy bears than 3 times the number of dolls “𝑑”. The next store has 2 more than twice the number of teddy bears. If there are 6 dolls, how many teddy bears does the second store have?

Answer: 30

Step-by-step solution

Step 1: Express teddy bears in the first store

The first toy store has 4 fewer teddy bears than 3 times the number of dolls $d$ . We translate this statement into an algebraic expression: multiply the number of dolls $d$ by 3 and then subtract 4.

Step 2: Calculate teddy bears in the first store for $d = 6$

We are given that the number of dolls is $d = 6$ . Substituting $6$ in place of $d$ , we calculate $3 \times 6 = 18$ , and subtracting 4 gives $14$ teddy bears in the first store.

Step 3: Calculate teddy bears in the second store

The second store has 2 more than twice the number of teddy bears in the first store ( $T_1$ ). Twice 14 is $2 \times 14 = 28$ , and adding 2 gives $30$ teddy bears.

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A toy store has 4 fewer teddy bears than 3 times the number of dolls “𝑑”. The next store has 2 more than twice the number of teddy bears. If there are 6 dolls, how many teddy bears does the second store have?

Step-by-step solution

Step 1: Express teddy bears in the first store

Step 2: Calculate teddy bears in the first store for d=6d = 6d=6

Step 3: Calculate teddy bears in the second store

Step 2: Calculate teddy bears in the first store for $d = 6$