A triangle ABC is drawn to circumscribe a circle of radius 4 cm such that BD = 8 cm and DC = 6 cm. Find the sides AB and AC.
Answer: The sides AB and AC are 15 cm and 13 cm respectively.
Step-by-step solution
Step 1: Identify Tangent Properties
According to the property of tangents drawn from an external point to a circle, the lengths of the tangents from the external point to the circle are equal. Here, the vertices A, B, and C are external points. So, , , and . We are given and . Let AE = AF = x.
Step 2: Express Sides in terms of x
Now we can express the lengths of the sides of the triangle ABC in terms of . Side is the sum of and , which is . Side is the sum of and , which is . Side is the sum of and , which is .
Step 3: Calculate Semi-perimeter (s)
The semi-perimeter of the triangle is half the sum of its sides. Substituting the expressions for , , and , we get , which simplifies to .
Step 4: Calculate Area using Heron's Formula
We use Heron's formula to calculate the area of triangle ABC. Substituting the values of , , , and into the formula , we simplify the expression to .
Step 5: Calculate Area using Radius and Semi-perimeter
Alternatively, the area of a triangle that circumscribes a circle can also be calculated using the formula , where is the inradius and is the semi-perimeter. Given the radius and , the area is $4(x+14).
Step 6: Equate Areas and Solve for x
By equating the two expressions for the area of triangle ABC, we get . Squaring both sides and simplifying, we arrive at , which gives , so . We can divide by because represents a length, so , making x+14 .
Step 7: Calculate Sides AB and AC
Finally, substitute the value of back into the expressions for and . This gives and AC = 7 + 6 = 13 .
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