8532−23586174\begin{array}{r} 8532 \\ - 2358 \\ \hline 6174 \end{array} Takes 7 rounds Q3 We are .......... 50,00050{,}000? 5 digits number between 35,00035{,}000 and 75,00075{,}000. All digits are odd: 1,3,5,7,91, 3, 5, 7, 9. Largest number = 7399973999 Smallest number = 3511135111 Number closest to 50,000=49,99950{,}000 = 49{,}999

Answer: Largest number = 7399973{}999, Smallest number = 3511135{}111, Number closest to 50000=5111150{}000 = 51{}111

Step-by-step solution

Step 1: Find the largest number

To make the number strictly less than 7500075{}000 using only odd digits {1,3,5,7,9}\{1, 3, 5, 7, 9\}, the ten-thousands digit can be at most 77. Since the number must be less than 7500075{}000, if the first digit is 77, the thousands digit cannot be 55 or higher, so the maximum possible odd digit for the thousands place is 33. To maximize the rest of the number, the remaining digits in the hundreds, tens, and units places are all chosen as 99.

Step 2: Find the smallest number

To make the number strictly greater than 3500035{}000 using only odd digits {1,3,5,7,9}\{1, 3, 5, 7, 9\}, the smallest possible ten-thousands digit is 33. If the first digit is 33, the thousands digit must be at least 55 (since choosing 11 or 33 would make the number smaller than 3500035{}000). Thus, the thousands digit is 55. To minimize the remaining places, we choose the smallest odd digit, which is 11, for the hundreds, tens, and units places.

Step 3: Find the number closest to 50,000

We need all digits to be odd. A number just below 5000050{}000 would have to start with 33 (since 44 is even), making the closest number below 5000050{}000 equal to 3999939{}999, which is at a distance of 1000110{}001. A number just above 5000050{}000 can start with 55, followed by the smallest odd digits, giving 5111151{}111, which is at a distance of only 11111{}111. Comparing the two distances, 1111<100011{}111 < 10{}001, so the number closest to 5000050{}000 is 5111151{}111. Note that 4999949{}999 is invalid because its first digit 44 is even.

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