Using the zero-product property, either x = 0 or x² + 14 = 0. Solving x² + 14 = 0 gives x² = -14, which yields imaginary roots x = ± i√14. Over the real numbers, the only solution is x = 0.

Can you solve Xpower3+ $28x-14x=0$

Answer: Real solution: $x = 0$ (or complex solutions: $x = 0, \pm i\sqrt{14}$ )

Step-by-step solution

Step 1: Combine like terms

We combine the linear terms $28x$ and $-14x$ by performing $28 - 14 = 14$ . This simplifies the equation to $x^3 + 14x = 0$ .

Step 2: Factor out the common term

Both terms share a common factor of $x$ . We factor $x$ out of the expression, resulting in $x(x^2 + 14) = 0$ .

Step 3: Solve for x

Using the zero-product property, either $x = 0$ or $x^2 + 14 = 0$ . Solving $x^2 + 14 = 0$ gives $x^2 = -14$ , which yields imaginary roots $x = \pm i\sqrt{14}$ . Over the real numbers, the only solution is $x = 0$ .

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Can you solve Xpower3+ 28x−14x=028x-14x=028x−14x=0

Step-by-step solution

Step 1: Combine like terms

Step 2: Factor out the common term

Step 3: Solve for x

Can you solve Xpower3+ $28x-14x=0$