d) The sum …\dots 9779 Ans: Digits=1,2,3,5\text{Digits} = 1, 2, 3, 5 L=5,321L = 5{,}321 S=1235S = 1235 Sum=6556<9779\text{Sum} = 6556 < 9779 --- Q2. What is the …\dots difference? Ans: Smallest 5 digit palindrome =10001= 10001 Large 5 digit palindrome =99999= 99999 Sum=10001+99999=110000\text{Sum} = 10001 + 99999 = 110000 Difference=99999−10001=89998\text{Difference} = 99999 - 10001 = 89998 --- Q3. The time …\dots after that Ans: Time now=10:01\text{Time now} = 10:01 Next Palindrome=11:11\text{Next Palindrome} = 11:11 Difference=11:11−10:01=70 min=1 hour 10 min\text{Difference} = 11:11 - 10:01 = 70 \text{ min} = 1 \text{ hour } 10 \text{ min} Next one is 12:2112:21, after 2 hours 10 min2 \text{ hours } 10 \text{ min}. --- Q4. How many …\dots Ans: 86537785−3568−13−2050856360\begin{array}{r r r} 8653 & 77 & 85 \\ - 3568 & - 13 & - 2\phantom{0} \\ \hline 5085 & 63 & 6\phantom{0} \end{array}

Answer: Sum = 110000, Difference = 89998

Step-by-step solution

Step 1: Identify the smallest 5-digit palindrome

A 55 -digit number has the form abcba, where the first digit aa cannot be 00. To minimize the number, we choose the smallest non-zero digit for aa, which is 11. To make the middle digits as small as possible, we choose b=0b = 0 and c=0c = 0, giving 1000110001.

Step 2: Identify the largest 5-digit palindrome

To maximize a 55 -digit number of the form abcba, each digit should be as large as possible. The largest single digit is 99, so setting a=9a = 9, b=9b = 9, and c=9c = 9 gives the palindrome 9999999999.

Step 3: Calculate the sum

Adding the smallest 55 -digit palindrome 1000110001 to the largest 55 -digit palindrome 9999999999 gives 10001+99999=11000010001 + 99999 = 110000.

Step 4: Calculate the difference

Subtracting the smallest 55 -digit palindrome 1000110001 from the largest 55 -digit palindrome 9999999999 gives 99999−10001=8999899999 - 10001 = 89998.

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