Define the function f:R→Rf: \mathbf{R} \rightarrow \mathbf{R} by y=f(x)=x2,x∈Ry=f(x)=x^{2}, x \in \mathbf{R}. Complete the Table given below by using this definition. What is the domain and range of this function? Draw the graph of ff. x−4−3−2−101234y=f(x)=x2\begin{array}{|l|l|l|l|l|l|l|l|l|l|} \hline x & -4 & -3 & -2 & -1 & 0 & 1 & 2 & 3 & 4 \\ \hline y=f(x)=x^{2} & & & & & & & & & \\ \hline \end{array}

Answer: The completed table is: x−4−3−2−101234y=f(x)=x216941014916\begin{array}{|l|l|l|l|l|l|l|l|l|l|}\hline x & -4 & -3 & -2 & -1 & 0 & 1 & 2 & 3 & 4 \\ \hline y=f(x)=x^{2} & 16 & 9 & 4 & 1 & 0 & 1 & 4 & 9 & 16 \\ \hline \end{array} . The domain of the function is R\mathbf{R} and the range is[0,\text{and the range is}[0, ∞\infty). The graph of f(x) = x2x^2 is a parabola opening upwards with its vertex at the origin(0{,}0).

Step-by-step solution

Step 1: Understand the Function Definition

The problem defines a function ff from the set of real numbers R\mathbf{R} to the set of real numbers R\mathbf{R} , given by the equation y=f(x)=x2y = f(x) = x^2 . This means for any input value xx , the output yy is the square of xx .

Step 2: Complete the Table

To complete the table, we substitute each given xx value into the function f(x)=x2f(x) = x^2 and calculate the corresponding yy value. For example, if x=−4x = -4 , then y=(−4)2=16y = (-4)^2 = 16 . If x=3x = 3 , then y=(3)2=9y = (3)^2 = 9 .

Step 3: Determine Domain and Range

The domain of a function is the set of all possible input values ( xx ). Since we can square any real number, the domain of f(x)=x2f(x) = x^2 is all real numbers, denoted by R\mathbf{R} . The range is the set of all possible output values ( yy ). Since the square of any real number is always non-negative, the range of f(x)=x2f(x) = x^2 is all non-negative real numbers, which can be written as [0,∞)[0, \infty) .

Step 4: Draw the Graph of the Function

Using the points from the completed table, we can plot them on a coordinate plane. Connecting these points with a smooth curve reveals that the graph of f(x)=x2f(x) = x^2 is a parabola. This parabola opens upwards, is symmetric about the yy -axis, and has its lowest point, or vertex, at the origin (0,0)(0{,}0) .

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