Define the real valued function f:R−{0}→Rf: \mathbf{R}-\{0\} \rightarrow \mathbf{R} defined by f(x)=1xf(x)=\frac{1}{x}, x∈R−{0}x \in \mathbf{R}-\{0\}. Complete the Table given below using this definition. What is the domain and range of this function? x−2−1.5−1−0.50.250.511.52y=1x………………………\begin{array}{|l|c|c|c|c|c|c|c|c|c|} \hline x & -2 & -1.5 & -1 & -0.5 & 0.25 & 0.5 & 1 & 1.5 & 2 \\ \hline y=\frac{1}{x} & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots & \ldots \\ \hline \end{array}

Answer: The completed table is: x−2−1.5−1−0.50.250.511.52y=1x−0.5−0.67−1−24210.670.5\begin{array}{|l|c|c|c|c|c|c|c|c|c|}\hline x & -2 & -1.5 & -1 & -0.5 & 0.25 & 0.5 & 1 & 1.5 & 2 \\ \hline y=\frac{1}{x} & -0.5 & -0.67 & -1 & -2 & 4 & 2 & 1 & 0.67 & 0.5 \\ \hline \end{array} The domain of the function is R−{0}\mathbf{R}-\{0\}. The range of the function is R−{0}\mathbf{R}-\{0\}.

Step-by-step solution

Step 1: Understand the Function Definition

The given function is f(x)=1xf(x) = \frac{1}{x} . This means that for any input value xx , the output f(x) is its reciprocal. The domain is specified as R−{0}\mathbf{R}-\{0\} , which means all real numbers except 00 , because division by zero is undefined.

Step 2: Calculate Function Values for Negative x

We substitute each negative value of xx from the table into the function f(x)=1xf(x) = \frac{1}{x} to find the corresponding yy values. For example, when x=−2x = -2 , f(−2)=1−2=−0.5f(-2) = \frac{1}{-2} = -0.5 .

Step 3: Calculate Function Values for Positive x

Similarly, we substitute each positive value of xx from the table into the function f(x)=1xf(x) = \frac{1}{x} to find the corresponding yy values. For example, when x=0.25x = 0.25 , f(0.25)=10.25=4f(0.25) = \frac{1}{0.25} = 4 .

Step 4: Complete the Table

By combining all the calculated values, we can complete the given table. The values are rounded to two decimal places where necessary.

Step 5: Determine Domain and Range

The domain of the function f(x)=1xf(x) = \frac{1}{x} is given as all real numbers except 00 , because division by zero is undefined. The range of the function is also all real numbers except 00 , because f(x) can never be 00 (since 1/x=01/x = 0 has no solution) and can take any other real value.

More from this chapter

All Relations and Functions solutions →

Solve your own maths question free →