Discuss the continuity of the function ff given by f(x)=x3+x2−1f(x)=x^{3}+x^{2}-1.

Answer: The function f(x)=x3+x2−1f(x)=x^{3}+x^{2}-1 is continuous for all real numbers.

Step-by-step solution

Step 1: Identify the function type

The given function is f(x)=x3+x2−1f(x) = x^3 + x^2 - 1. This is a polynomial function, as it consists of terms involving non-negative integer powers of xx combined with addition and subtraction.

Step 2: Recall continuity property of polynomials

A fundamental property of polynomial functions is that they are continuous for all real numbers. This means that for any real number cc, the limit of the function as xx approaches cc exists and is equal to the function's value at cc, i.e., lim⁡x→cf(x)=f(c)\lim_{x \to c} f(x) = f(c).

Step 3: Conclusion on continuity

Since f(x)=x3+x2−1f(x) = x^3 + x^2 - 1 is a polynomial function, it is continuous for all real numbers. There are no points where the function is undefined or where its graph would have a break.

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