Evaluate ∫₀^(π/2) (sin x)^4 (cos x)^3 dx using reduction formulas.

Answer: 235\frac{2}{35}

Step-by-step solution

Step 1: Rewrite the integral

The integral involves powers of sin⁡x\sin x and cos⁡x\cos x. Since the power of cos⁡x\cos x is odd, we can separate one cos⁡x\cos x term and convert the remaining even power of cos⁡x\cos x into sin⁡x\sin x using the identity cos⁡2x=1−sin⁡2x\cos^2 x = 1 - \sin^2 x.

Step 2: Substitute using trigonometric identity

Substitute cos⁡2x=1−sin⁡2x\cos^2 x = 1 - \sin^2 x into the integral. This transforms the integral into a form suitable for a substitution.

Step 3: Perform substitution

Let u=sin⁡xu = \sin x. Then, du=cos⁡xdxdu = \cos x dx. We also need to change the limits of integration. When x=0x=0, u=sin⁡0=0u=\sin 0 = 0. When x=π/2x=\pi/2, u=sin⁡(π/2)=1u=\sin (\pi/2) = 1. The integral now becomes a polynomial in uu.

Step 4: Expand and integrate

Expand the integrand and then integrate term by term using the power rule for integration, ∫undu=un+1n+1\int u^n du = \frac{u^{n+1}}{n+1}.

Step 5: Evaluate the definite integral

Substitute the upper and lower limits of integration into the integrated expression and subtract the lower limit value from the upper limit value to find the definite integral's result.

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