Evaluate ∣24−12∣\left|\begin{array}{rr}2 & 4 \\ -1 & 2\end{array}\right|.

Answer: 8

Step-by-step solution

Step 1: Identify the determinant formula for a 2x2 matrix

To evaluate a 2×22 \times 2 determinant, we use a specific formula. If the matrix is given as (abcd)\begin{pmatrix} a & b \\ c & d \end{pmatrix}, its determinant is calculated by multiplying the elements on the main diagonal (a×da \times d) and subtracting the product of the elements on the anti-diagonal (b×cb \times c).

Step 2: Identify the elements of the given matrix

From the given determinant ∣24−12∣\left|\begin{array}{rr}2 & 4 \\ -1 & 2\end{array}\right|, we can identify the values of a,b,c,a, b, c, and dd. Here, a=2a=2, b=4b=4, c=−1c=-1, and d=2d=2.

Step 3: Substitute the values into the formula

Now, substitute the identified values of a,b,c,a, b, c, and dd into the determinant formula ad−bcad - bc. This gives us (2)(2)−(4)(−1)(2)(2) - (4)(-1).

Step 4: Calculate the products

Perform the multiplications: 2×2=42 \times 2 = 4 and 4×(−1)=−44 \times (-1) = -4. So the expression becomes 4−(−4)4 - (-4).

Step 5: Simplify the expression

Subtracting a negative number is equivalent to adding its positive counterpart. Therefore, 4−(−4)4 - (-4) simplifies to 4+44 + 4, which equals 88.

More from this chapter

All Determinants solutions →

Solve your own maths question free →