Evaluate the definite integral \int_{0}^{\frac{\pi}{2}} \frac{\sqrt{\sin x}}{\sqrt{\sin x} + \sqrt{\cos x}} dx.
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Step-by-Step Solution
Step 1: Define the integral
Let the given definite integral be denoted by $I$. This is the standard way to begin solving definite integral problems, especially when properties of definite integrals are to be applied.
Step 2: Apply the property of definite integrals
We apply the property of definite integrals which states that $\int_{a}^{b} f(x) dx = \int_{a}^{b} f(a+b-x) dx$. In this case, $a=0$ and $b=\frac{\pi}{2}$, so $a+b-x = \frac{\pi}{2}-x$. We substitute this into the integral.
Step 3: Simplify the integral using trigonometric identities
Using the trigonometric identities $\sin(\frac{\pi}{2}-x) = \cos x$ and $\cos(\frac{\pi}{2}-x) = \sin x$, we simplify the integrand. This gives us a new expression for $I$, which we label as equation (2).
Step 4: Add the two integral equations
We add equation (1) and equation (2) together. Since the limits of integration are the same, we can combine the integrands. Notice that the denominators are identical.
Step 5: Simplify and evaluate the integral
The numerator and denominator of the combined integrand are identical, so the fraction simplifies to $1$. We then integrate $1$ with respect to $x$, which gives $x$. Evaluating this from $0$ to $\frac{\pi}{2}$ yields $\frac{\pi}{2}$.
Step 6: Solve for I
Finally, we divide both sides by $2$ to find the value of $I$, which is $\frac{\pi}{4}$.