To prime factorise 56, we divide successively by the smallest prime numbers: 56 ÷ 2 = 28, 28 ÷ 2 = 14, 14 ÷ 2 = 7, and 7 is prime. Hence, the prime factorisation of 56 is 2³ × 7.

Find all the Prime factorsation of 56×25

Answer: $2^3 \times 5^2 \times 7$

Step-by-step solution

Step 1: Prime factorise 56

To prime factorise 56, we divide successively by the smallest prime numbers: $56 \div 2 = 28$ , $28 \div 2 = 14$ , $14 \div 2 = 7$ , and 7 is prime. Hence, the prime factorisation of 56 is $2^3 \times 7$ .

Step 2: Prime factorise 25

Next, we find the prime factors of 25. Since 25 is divisible by 5, we have $25 = 5^2$ .

Step 3: Combine the prime factors

We combine the prime factors of both numbers and arrange the prime bases in ascending order. This gives $2^3 \times 5^2 \times 7$ , or $2 \times 2 \times 2 \times 5 \times 5 \times 7$ .

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