Find dydx\frac{d y}{d x}, if x=at2,y=2atx=a t^{2}, y=2 a t.

Answer: dydx=1t\frac{d y}{d x} = \frac{1}{t}

Step-by-step solution

Step 1: Differentiate x with respect to t

We are given xx as a function of tt, specifically x=at2x = at^2. To find dxdt\frac{dx}{dt}, we differentiate at2at^2 with respect to tt. Using the power rule for differentiation, ddt(tn)=ntn−1\frac{d}{dt}(t^n) = nt^{n-1}, we get 2at2at.

Step 2: Differentiate y with respect to t

Next, we differentiate yy with respect to tt. Given y=2aty = 2at, its derivative with respect to tt is 2a2a, as aa is a constant and the derivative of tt with respect to tt is 11.

Step 3: Apply the Chain Rule

To find dydx\frac{dy}{dx}, we use the chain rule for parametric equations. This rule states that dydx\frac{dy}{dx} can be found by dividing dydt\frac{dy}{dt} by dxdt\frac{dx}{dt}.

Step 4: Substitute and Simplify

Now, we substitute the expressions we found for dydt\frac{dy}{dt} and dxdt\frac{dx}{dt} into the chain rule formula. After substitution, we simplify the expression by canceling out common terms.

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