Find the area of a triangular park ABC with sides 50m, 80m, and 120m using Heron's formula.

Answer: The area of the triangular park is approximately 1452.36 m21452.36\text{ m}^2.

Step-by-step solution

Step 1: Calculate the semi-perimeter

Heron's formula requires the semi-perimeter, denoted by ss. This is half the sum of the lengths of the three sides of the triangle. Given the side lengths a=50 ma = 50\text{ m}, b=80 mb = 80\text{ m}, and c=120 mc = 120\text{ m}, we sum them up and divide by 2.

Step 2: Substitute values into semi-perimeter formula

Substituting the given side lengths into the formula, we get s=50+80+1202=2502=125 ms = \frac{50 + 80 + 120}{2} = \frac{250}{2} = 125\text{ m}.

Step 3: Apply Heron's formula

Heron's formula provides a way to calculate the area of a triangle when only the lengths of its three sides are known. The formula is Area=s(s−a)(s−b)(s−c)\text{Area} = \sqrt{s(s-a)(s-b)(s-c)}, where ss is the semi-perimeter and a,b,ca, b, c are the side lengths.

Step 4: Substitute values into Heron's formula

Now we substitute the calculated semi-perimeter s=125 ms = 125\text{ m} and the given side lengths a=50 ma = 50\text{ m}, b=80 mb = 80\text{ m}, c=120 mc = 120\text{ m} into Heron's formula.

Step 5: Calculate the area

Performing the subtractions inside the parentheses and then multiplying the terms, we get Area=125×75×45×5=2109375\text{Area} = \sqrt{125 \times 75 \times 45 \times 5} = \sqrt{2109375}. Finally, we calculate the square root to find the area, which is approximately 1452.36 m21452.36\text{ m}^2.

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