Find the derivative of f(x)=x+1xf(x)=\frac{x+1}{x}

Answer: f′(x)=−1x2f'(x) = -\frac{1}{x^2}

Step-by-step solution

Step 1: Rewrite the function

First, we can simplify the given function by splitting the fraction into two terms. This makes it easier to apply the power rule for differentiation. We rewrite 1x\frac{1}{x} as x−1x^{-1}.

Step 2: Apply the sum rule of differentiation

The derivative of a sum of functions is the sum of their derivatives. So, we can differentiate each term separately.

Step 3: Differentiate each term

The derivative of a constant (like 1) is always 0. For the term x−1x^{-1}, we use the power rule, which states that ddx(xn)=nxn−1\frac{d}{dx}(x^n) = nx^{n-1}. Here, n=−1n = -1, so we get −1⋅x−1−1=−x−2-1 \cdot x^{-1-1} = -x^{-2}.

Step 4: Combine the derivatives

Finally, we combine the derivatives of the individual terms to get the derivative of the original function.

Step 5: Rewrite in positive exponent form

It is good practice to express the final answer with positive exponents, so we rewrite x−2x^{-2} as 1x2\frac{1}{x^2}.

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