Find the derivative of the function given by f(x)=sin⁡(x2)f(x)=\sin \left(x^{2}\right).

Answer: f′(x)=2xcos⁡(x2)f'(x) = 2x \cos(x^2)

Step-by-step solution

Step 1: Identify the function and rule

The given function is f(x)=sin⁡(x2)f(x) = \sin(x^2). This is a composite function, meaning it's a function within a function. To differentiate such functions, we need to use the chain rule.

Step 2: Apply the Chain Rule

The chain rule states that the derivative of a composite function f(g(x))f(g(x)) is the derivative of the outer function ff evaluated at the inner function g(x)g(x), multiplied by the derivative of the inner function g(x)g(x). In our case, the outer function is sin⁡(u)\sin(u) and the inner function is u=x2u = x^2.

Step 3: Differentiate the outer function

First, we differentiate the outer function, sin⁡(u)\sin(u), with respect to uu. The derivative of sin⁡(u)\sin(u) is cos⁡(u)\cos(u).

Step 4: Differentiate the inner function

Next, we differentiate the inner function, x2x^2, with respect to xx. Using the power rule, the derivative of x2x^2 is 2x2x.

Step 5: Combine the derivatives

Finally, we combine the results from differentiating the outer and inner functions according to the chain rule. We substitute u=x2u = x^2 back into the derivative of the outer function and multiply it by the derivative of the inner function.

Step 6: Simplify the expression

Rearranging the terms gives us the final simplified derivative of the function.

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