Find the dimensions of the prayer hall discussed in Section 4.1. (The breadth satisfies .)
Answer: The breadth of the prayer hall is m and the length is m.
Step-by-step solution
Step 1: State the given quadratic equation
We are given a quadratic equation that represents the breadth of the prayer hall. We need to solve this equation to find the value of .
Step 2: Compare with standard quadratic equation
To solve the quadratic equation, we first identify the coefficients , , and by comparing it with the standard form of a quadratic equation.
Step 3: Identify coefficients
From the given equation , we can see that , , and .
Step 4: Apply the quadratic formula
The quadratic formula is used to find the roots of a quadratic equation. We substitute the values of , , and into this formula.
Step 5: Substitute values into the formula
Substitute the identified coefficients , , and into the quadratic formula.
Step 6: Simplify the expression under the square root
First, calculate the term inside the square root: and . Then, . The denominator is .
Step 7: Calculate the square root
The square root of 2401 is 49. This simplifies the expression further.
Step 8: Solve for x using both positive and negative roots
Now we have two possible values for : one by taking the positive square root and one by taking the negative square root.
Step 9: Calculate the first possible value of x
For the first root, we use the positive sign. gives , and divided by equals .
Step 10: Calculate the second possible value of x
For the second root, we use the negative sign. gives , and divided by equals .
Step 11: Determine the valid breadth
Since represents the breadth of the prayer hall, it cannot be a negative value. Therefore, we discard and take metres as the breadth.
Step 12: Find the length of the hall
From Section 4.1 of the textbook, the length of the prayer hall is given as 'one metre more than twice its breadth', so Length .
Step 13: Substitute the value of x to find the length
Substitute metres into the expression for the length to calculate its value.
More from this chapter
- find two natural numbers the sum of 4 squares is 25 times the sum and also equal to 3 times the difference
- Split middle term and factorize X square + 32 x minus 420 is equal 0
- divide 16 into 2 parts such that the twice the square of the largest part exceeds the square of the smaller part by 164
- एक्स स्क्वायर + 24 + 12 सॉल्व करो
- Solve: x² − 5x + 6 = 0 vdhsjv
- Solve: x² − 5x + 6 = l don't know
- 19. The perimeter of a right triangle is 60 cm and its hypotenuse is 25 cm. Find the lengths of other two sides of the triangle.
- The time taken by a person to travel an upward distance of 150 km was 2(1)/(2) hours more than the time taken in the downward return journey. If he returned at