Find the equation of the hyperbola where foci are (0, +-6) and the length of the latus rectum is 36.
Answer: The equation of the hyperbola is .
Step-by-step solution
Step 1: Identify key parameters from foci
The given foci of the hyperbola are . For a hyperbola with foci on the -axis, the standard form of the foci is . By comparing these, we can determine the value of .
Step 2: Use latus rectum length to find a relationship between a and b
The length of the latus rectum for a hyperbola is given by the formula . We are given that the length of the latus rectum is . We can set up an equation using this information to find a relationship between and .
Step 3: Apply the relationship between a, b, and c
For a hyperbola, the relationship between , , and is . We can substitute the value of and the expression for from the previous steps into this equation to form a quadratic equation in terms of .
Step 4: Solve the quadratic equation for a
We solve the quadratic equation for using the quadratic formula. Since represents a length, it must be a positive value. We select the positive root from the two solutions.
Step 5: Calculate and
Now that we have the value of , we can calculate . Then, using the relationship from step 2, we can find the value of .
Step 6: Write the equation of the hyperbola
Since the foci are on the -axis, the standard equation of the hyperbola is . We substitute the calculated values of and into this equation to get the final equation of the hyperbola.
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