Find the sum of the first 20 terms of the AP: 5, 8, 11, 14, and so on.

Answer: The sum of the first 20 terms of the given AP is 670.

Step-by-step solution

Step 1: Identify the given values

First, we identify the values provided in the problem. The first term (aa) is 5. The common difference (dd) is found by subtracting any term from its succeeding term, so 8−5=38 - 5 = 3. We need to find the sum of the first 20 terms, which means n=20n = 20.

Step 2: Recall the formula for the sum of an AP

The formula for the sum of the first nn terms of an arithmetic progression (SnS_n) is given by Sn=n2[2a+(n−1)d]S_n = \frac{n}{2} [2a + (n-1)d]. This formula allows us to calculate the sum directly using the first term, common difference, and number of terms.

Step 3: Substitute the values into the formula

Now we substitute the identified values into the sum formula. We replace aa with 5, dd with 3, and nn with 20. This prepares the expression for calculation.

Step 4: Perform the calculations

We simplify the expression step-by-step. First, calculate 202=10\frac{20}{2} = 10. Then, inside the bracket, calculate 2×5=102 \times 5 = 10 and (20−1)×3=19×3=57(20-1) \times 3 = 19 \times 3 = 57. Add these two results: 10+57=6710 + 57 = 67. Finally, multiply by 10 to get the sum: 10×67=67010 \times 67 = 670.

More from this chapter

All Arithmetic Progressions solutions →

Solve your own maths question free →