find two natural numbers the sum of 4 squares is 25 times the sum and also equal to 3 times the difference

Answer: The two natural numbers are 10 and 5.

Step-by-step solution

Step 1: Analyze the conditions and formulate the system

Let the two natural numbers be xx and yy such that x>yx > y. The prompt contains typographical ambiguity: 'the sum of 4 squares is 25 times the sum and also equal to 3 times the difference'. In classic algebra problems, this reads as: 'the sum of their squares is 2525 times their difference, and the sum of the numbers is 33 times their difference' or x2+y2=25(x+y)x^2 + y^2 = 25(x + y) and related conditions.

Step 2: Examine the linear relationship between sum and difference

In standard problems of this type, the sum of the numbers is 33 times their difference: x+y=3(x−y)x + y = 3(x - y). Expanding this gives x+y=3x−3yx + y = 3x - 3y, which simplifies directly to 2x=4y2x = 4y, meaning x=2yx = 2y.

Step 3: Substitute into the sum of squares equation

Using the relation that the sum of their squares is 2525 times their difference, we substitute x=2yx = 2y. This gives (2y)2+y2=25(2y−y)(2y)^2 + y^2 = 25(2y - y), which simplifies to 4y2+y2=25y4y^2 + y^2 = 25y, or 5y2=25y5y^2 = 25y.

Step 4: Solve for the two natural numbers

Since yy is a natural number, y≠0y \neq 0, which gives y=5y = 5. Substituting y=5y = 5 into x=2yx = 2y yields x=10x = 10. Checking the conditions: the sum of squares is 102+52=12510^2 + 5^2 = 125, the difference is 10−5=510 - 5 = 5, and 25×5=12525 \times 5 = 125. Also, the sum is 10+5=15=3×510 + 5 = 15 = 3 \times 5. Both conditions are satisfied.

Solve your own maths question free →