Using prime factorisation, dividing 112 repeatedly by the smallest prime numbers gives 2^4 × 7^1. The total number of factors can be calculated using the exponents: (4 + 1) × (1 + 1) = 5 × 2 = 10 factors.

Using prime factorisation, dividing 112 repeatedly by the smallest prime numbers gives 2^4 × 7^1. The total number of factors can be calculated using the exponents: (4 + 1) × (1 + 1) = 5 × 2 = 10 factors.

how to find factors of any numbers 112 easily

Answer: The factors of $112$ are $1, 2, 4, 7, 8, 14, 16, 28, 56, 112$ .

Step-by-step solution

Step 1: Find factors using multiplication pairs

To find all the factors easily, we test integers starting from $1$ up to $\sqrt{112} \approx 10.58$ to check which divide $112$ completely. We write each division as a multiplication pair. Numbers like $3$ , $5$ , $6$ , $9$ , and $10 do$ not divide $112$ without leaving a remainder.

Step 2: Verify by prime factorisation

Using prime factorisation, dividing $112$ repeatedly by the smallest prime numbers gives $2^4 \times 7^1$ . The total number of factors can be calculated using the exponents: $(4 + 1) \times (1 + 1) = 5 \times 2 = 10$ factors.

Step 3: List all factors in ascending order

Collecting all the numbers from our factor pairs in increasing order gives the complete set of $10$ positive factors of $112$ .

Solve your own maths question free →