If $5x + 08y = 42$ and $x = 4$ what is the value of y?

Step 1: Substitute the value of x

The problem provides the equation $5x + 8y = 42$ and states that $x = 4$. To find the value of $y$, we first substitute the given value of $x$ into the equation. Note that $08y$ is equivalent to $8y$.

Step 2: Simplify the equation

After substituting $x=4$, we multiply $5$ by $4$ to simplify the term $5x$. This gives us $20$, resulting in the simplified equation $20 + 8y = 42$.

Step 3: Isolate the term with y

To isolate the term containing $y$, we need to move the constant term $20$ to the right side of the equation. We do this by subtracting $20$ from both sides.

Step 4: Calculate the difference

Now, we perform the subtraction on the right side of the equation: $42 - 20 = 22$. This simplifies the equation to $8y = 22$.

Step 5: Solve for y

Finally, to find the value of $y$, we divide both sides of the equation by $8$. This isolates $y$ and gives us its numerical value. The fraction can be further simplified.

Step 6: Simplify the fraction

The fraction $\frac{22}{8}$ can be simplified by dividing both the numerator and the denominator by their greatest common divisor, which is $2$. So, $22 \div 2 = 11$ and $8 \div 2 = 4$.

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