If A=[[1,2],[3,4]]A = [[1, 2], [3, 4]] find det⁡(A)\det(A) and adj(A)\text{adj}(A).

Answer: The determinant of AA is −2-2 and the adjoint of AA is (4−2−31)\begin{pmatrix} 4 & -2 \\ -3 & 1 \end{pmatrix} .

Step-by-step solution

Step 1: Calculate the Determinant of A

For a 2×22 \times 2 matrix A=(abcd)A = \begin{pmatrix} a & b \\ c & d \end{pmatrix}, the determinant is calculated as the product of the elements on the main diagonal minus the product of the elements on the anti-diagonal. Here, a=1a=1, b=2b=2, c=3c=3, and d=4d=4.

Step 2: Substitute values and compute determinant

Substitute the values a=1a=1, b=2b=2, c=3c=3, and d=4d=4 into the determinant formula. This gives us (1)(4) - (2)(3), which simplifies to 4 - 6 = -2.

Step 3: Calculate the Adjoint of A

For a 2×22 \times 2 matrix A=(abcd)A = \begin{pmatrix} a & b \\ c & d \end{pmatrix}, the adjoint matrix is found by swapping the elements on the main diagonal (aa and dd) and changing the signs of the elements on the anti-diagonal (bb and cc).

Step 4: Substitute values into the adjoint formula

Substitute the values a=1a=1, b=2b=2, c=3c=3, and d=4d=4 into the adjoint formula. The element dd becomes the top-left, aa becomes the bottom-right, −b-b becomes the top-right, and −c-c becomes the bottom-left.

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