If A>B and their LCM is L RULES

Answer: For positive integers A>BA > B with LCM(A,B)=L\text{LCM}(A, B) = L: (1) LL is a common multiple: A∣LA \mid L and B∣LB \mid L; (2) Range: A≤L≤A×BA \le L \le A \times B; (3) If BB divides AA, then L=AL = A; (4) General relation: HCF(A,B)×L=A×B\text{HCF}(A, B) \times L = A \times B; (5) If HCF(A,B)=1\text{HCF}(A, B) = 1, then L=A×BL = A \times B.

Step-by-step solution

Step 1: Define divisibility and bounding rules

By definition, the least common multiple L=LCM(A,B)L = \text{LCM}(A, B) of two positive integers is a multiple of both AA and BB. Since AA and BB are positive non-zero integers with A>BA > B, the multiple LL must be at least as large as the greater number, which gives L≥A>BL \ge A > B.

Step 2: State the special case of divisibility

If the smaller number BB divides the larger number AA completely, then AA is already a common multiple of both AA and BB. Because AA is the smallest possible non-zero multiple of AA, the least common multiple is exactly L=AL = A.

Step 3: Relate LCM and HCF to the product of numbers

For any two positive integers AA and BB, the product of their highest common factor and their least common multiple equals the product of the two numbers. This fundamental identity allows us to compute LL or bound it using their greatest common divisor.

Step 4: State the rule for co-prime numbers

When AA and BB share no common prime factors, they are co-prime, meaning HCF(A,B)=1\text{HCF}(A, B) = 1. Substituting HCF(A,B)=1\text{HCF}(A, B) = 1 into the product formula yields the maximum possible value for the LCM, namely L=A×BL = A \times B.

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