If the four distinct points (4,6)(4{,}6), (−1,5)(-1{,}5), (0,0)(0{,}0) and (k,3k)(k,3k) lie on a circle of radius rr, then 10k+r210k + r^2 is equal to:

Answer: 35

Step-by-step solution

Step 1: General Equation of a Circle

The general equation of a circle is given by x2+y2+2gx+2fy+c=0x^2 + y^2 + 2gx + 2fy + c = 0. We can use the given points to form a system of equations to find the values of gg, ff, and cc. The center of the circle is (−g,−f)(-g, -f) and the radius rr is given by g2+f2−c\sqrt{g^2 + f^2 - c}.

Step 2: Substitute the given points into the equation

First, substitute the point (0,0)(0{,}0) into the general equation, which directly gives c=0c=0. Then, substitute the points (4,6)(4{,}6) and (−1,5)(-1{,}5) into the equation with c=0c=0 to obtain two linear equations in terms of gg and ff.

Step 3: Solve for g and f

Solve the system of linear equations for gg and ff. Multiply equation (2) by 2 and add it to equation (1) to eliminate gg and find ff. Then substitute the value of ff back into one of the equations to find gg.

Step 4: Find the radius r

With g=−2g=-2, f=−3f=-3, and c=0c=0, we can calculate the radius rr using the formula r=g2+f2−cr = \sqrt{g^2 + f^2 - c}.

Step 5: Substitute the fourth point (k, 3k) into the circle equation

Since the fourth point (k,3k)(k,3k) also lies on the circle, substitute its coordinates and the values of gg, ff, and cc into the general equation of the circle. This will allow us to solve for kk.

Step 6: Solve for k and calculate the final expression

Simplify the equation to solve for kk. Since the points are distinct, kk cannot be 00. Therefore, k=115k = \frac{11}{5}. Finally, substitute the values of kk and r2r^2 into the expression 10k+r210k + r^2 to get the final answer.

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