If the points A(x,y)A(x, y), B(1,3)B(1, 3), and C(3,1)C(3, 1) are vertices of a triangle whose area is 8 sq. units8\text{ sq. units}, show that: x+y=12orx+y=−4x+y=12\quad \text{or}\quad x+y=-4

Answer: The relationship between xx and yy is x+y=12x+y=12 or x+y=−4x+y=-4.

Step-by-step solution

Step 1: Recall the Area of a Triangle Formula

The area of a triangle with vertices (x1,y1)(x_1, y_1), (x2,y2)(x_2, y_2), and (x3,y3)(x_3, y_3) can be calculated using this formula. We will substitute the given coordinates and the area into this formula.

Step 2: Substitute Given Values into the Formula

We are given the vertices A(x,y)A(x, y), B(1,3)B(1, 3), and C(3,1)C(3, 1), and the area is 88 sq. units. We substitute these values into the area formula.

Step 3: Simplify the Expression

Multiply both sides by 2 to remove the fraction. Then, simplify the expression inside the absolute value by combining like terms.

Step 4: Solve for the two possible cases

Since the absolute value of an expression is 16, the expression itself can be either 1616 or −16-16. This gives us two separate linear equations to solve.

Step 5: Solve the first equation

For the first case, add 8 to both sides and then divide the entire equation by 2 to simplify it.

Step 6: Solve the second equation

For the second case, add 8 to both sides and then divide the entire equation by 2 to simplify it.

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