If the points A(x,y)A(x, y), B(2,3)B(2, 3), and C(3,2)C(3, 2) are vertices of a triangle whose area is 7 sq. units7\text{ sq. units}, show that: x+y=19orx+y=−9x+y=19\quad \text{or}\quad x+y=-9

Answer: The relationship between xx and yy is x+y=19x+y=19 or x+y=−9x+y=-9.

Step-by-step solution

Step 1: Recall the Area of a Triangle Formula

To find the area of a triangle given its vertices, we use the determinant formula. The absolute value ensures the area is always positive. We are given the vertices A(x,y)A(x, y), B(2,3)B(2, 3), and C(3,2)C(3, 2), and the area is 77 square units.

Step 2: Substitute the Given Coordinates and Area

Now, we substitute the coordinates of points A(x1,y1)=(x,y)A(x_1, y_1) = (x, y), B(x2,y2)=(2,3)B(x_2, y_2) = (2, 3), and C(x3,y3)=(3,2)C(x_3, y_3) = (3, 2) into the area formula. We also set the area equal to 77.

Step 3: Simplify the Expression Inside the Absolute Value

First, multiply both sides by 22 to remove the fraction. Then, simplify the terms inside the absolute value by performing the multiplications and combining like terms.

Step 4: Solve for Two Possible Cases

Since the expression is inside an absolute value, it can be either positive or negative 1414. This gives us two separate linear equations to solve.

Step 5: Solve Each Equation for x + y

For the first case, add 55 to both sides of the equation x+y−5=14x + y - 5 = 14. For the second case, add 55 to both sides of the equation x+y−5=−14x + y - 5 = -14. This yields the two required relationships.

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