If the system of equations has infinitely many solutions, then is equal to:
Answer: 29
Step-by-step solution
Step 1: Formulate the augmented matrix
To solve a system of linear equations, we can represent it using an augmented matrix. This matrix combines the coefficients of the variables and the constants on the right-hand side of the equations. The vertical line separates the coefficient matrix from the constant terms.
Step 2: Condition for infinitely many solutions
For a system of linear equations to have infinitely many solutions, two conditions must be met: the determinant of the coefficient matrix () must be zero, and the determinants of the matrices formed by replacing a column of with the constant terms () must also be zero. This ensures that the equations are consistent and dependent.
Step 3: Calculate determinant of coefficient matrix
We calculate the determinant of the coefficient matrix and set it to zero. This will give us a relationship between and . The determinant is calculated as .
Step 4: Solve for the relationship between and
Expanding the determinant from the previous step, we get an algebraic equation involving and . This equation represents the condition for the determinant of the coefficient matrix to be zero.
Step 5: Calculate determinant of
Now, we replace the first column of the coefficient matrix with the constant terms to form . We calculate its determinant and set it to zero. This will give us another equation involving and .
Step 6: Solve for and
Expanding the determinant of and simplifying, we get a second equation: . We now have two equations with two variables, and . We can solve these simultaneously. By comparing the coefficients of and in both equations, we can deduce that and .
Step 7: Calculate
Finally, we substitute the values of and into the expression to find the required value.
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