If xx, 2x+92x + 9, 4x+34x + 3 are three consecutive terms of an A.P., then the value of x is :

Answer: The value of x is 15.

Step-by-step solution

Step 1: Understand the property of an A.P.

In an Arithmetic Progression (A.P.), the difference between any two consecutive terms is constant. If aa, bb, and cc are three consecutive terms of an A.P., then the common difference can be expressed as b−ab - a or c−bc - b. Therefore, b−a=c−bb - a = c - b. This can also be written as 2b=a+c2b = a + c.

Step 2: Substitute the given terms into the A.P. property

Given the three consecutive terms as xx, 2x+92x + 9, and 4x+34x + 3, we can substitute these into the property 2b=a+c2b = a + c. Here, a=xa = x, b=2x+9b = 2x + 9, and c=4x+3c = 4x + 3.

Step 3: Simplify the equation

First, distribute the 2 on the left side of the equation: 2(2x)+2(9)=4x+182(2x) + 2(9) = 4x + 18. On the right side, combine the like terms: x+4x=5xx + 4x = 5x. So, the right side becomes 5x+35x + 3.

Step 4: Solve for x

To isolate xx, subtract 4x4x from both sides of the equation and subtract 33 from both sides of the equation. This gives 18−3=5x−4x18 - 3 = 5x - 4x, which simplifies to 15=x15 = x.

More from this chapter

All Arithmetic Progressions solutions →

Solve your own maths question free →