In a triangle ABC, if find the value of sin(A/2) and cos(A/2).
Answer: and .
Step-by-step solution
Step 1: Calculate the semi-perimeter (s)
To use the half-angle formulas for sine and cosine, we first need to calculate the semi-perimeter of the triangle, denoted by . The semi-perimeter is half the sum of the lengths of the three sides of the triangle.
Step 2: Substitute the side lengths
We substitute the given values of the side lengths , , and into the formula for and perform the addition and division to find its value.
Step 3: Apply the half-angle formula for sin(A/2)
Now we use the half-angle formula for , which relates the sine of half an angle to the side lengths and the semi-perimeter of the triangle. This formula is derived using the Law of Cosines and trigonometric identities.
Step 4: Substitute values into sin(A/2) formula
Substitute the calculated semi-perimeter and the given side lengths , into the formula. Then, perform the subtractions and multiplications within the square root.
Step 5: Simplify to find sin(A/2)
Simplify the fraction inside the square root. Since , the fraction becomes . Finally, take the square root and rationalize the denominator by multiplying the numerator and denominator by .
Step 6: Apply the half-angle formula for cos(A/2)
Next, we use the half-angle formula for . This formula, similar to the sine half-angle formula, connects the cosine of half an angle to the side lengths and the semi-perimeter of the triangle.
Step 7: Substitute values into cos(A/2) formula
Substitute the calculated semi-perimeter and the given side lengths , , into the formula. Then, perform the subtraction and multiplications within the square root.
Step 8: Simplify to find cos(A/2)
Simplify the fraction inside the square root by finding common factors. Both 648 and 720 are divisible by 72 ( and ). After simplification, take the square root of the numerator and denominator, and rationalize the denominator.
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