In the coordinate plane, triangle ABC is equilateral with B(1, 0) and C(3, 0). A line through the origin O meets AB and AC at M and N respectively. If OM = MN, find the coordinates of M.

Answer: The coordinates of M are (5/4,3/4)(5/4, \sqrt{3}/4).

Step-by-step solution

Step 1: Find coordinates of A and side length

First, we find the length of the side BC using the distance formula. Since triangle ABC is equilateral, all sides have length 2. The xx -coordinate of A is the midpoint of BC, which is (1+3)/2=2(1+3)/2 = 2. The yy -coordinate of A is the height of an equilateral triangle with side length a=2a=2, which is a3/2=23/2=3a\sqrt{3}/2 = 2\sqrt{3}/2 = \sqrt{3}.

Step 2: Determine equations of lines AB and AC

Next, we find the equations of lines AB and AC using the two-point form y−y1=y2−y1x2−x1(x−x1)y - y_1 = \frac{y_2 - y_1}{x_2 - x_1}(x - x_1). For line AB, we use points B(1,0) and A(2, 3\sqrt{3}). For line AC, we use points C(3,0) and A(2, 3\sqrt{3}).

Step 3: Use section formula for M and N

The problem states that OM = MN. This implies that M is the midpoint of the segment ON, where O is the origin (0,0). Therefore, if N has coordinates (xN,yN)(x_N, y_N), then M will have coordinates (xN/2,yN/2)(x_N/2, y_N/2).

Step 4: Substitute M and N into line equations

Since M lies on AB, its coordinates (xM,yM)(x_M, y_M) satisfy the equation of line AB. Substituting xM=xN/2x_M = x_N/2 and yM=yN/2y_M = y_N/2 into the equation for AB gives us a relationship between xNx_N and yNy_N. Since N lies on AC, its coordinates (xN,yN)(x_N, y_N) must also satisfy the equation of line AC.

Step 5: Solve for N and then M

Now we have two equations for yNy_N in terms of xNx_N. We can equate them to solve for xNx_N. Once xNx_N is found, we substitute it back into either equation to find yNy_N. Finally, we use the relationship M=(xN/2,yN/2)M = (x_N/2, y_N/2) to find the coordinates of M.

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