In the coordinate plane, triangle ABC is equilateral with B(1, 0) and C(3, 0). A line through the origin O meets AB and AC at M and N respectively. If OM = MN, find the coordinates of M.
Answer: The coordinates of M are .
Step-by-step solution
Step 1: Find coordinates of A and side length
First, we find the length of the side BC using the distance formula. Since triangle ABC is equilateral, all sides have length 2. The -coordinate of A is the midpoint of BC, which is . The -coordinate of A is the height of an equilateral triangle with side length , which is .
Step 2: Determine equations of lines AB and AC
Next, we find the equations of lines AB and AC using the two-point form . For line AB, we use points B(1,0) and A(2, ). For line AC, we use points C(3,0) and A(2, ).
Step 3: Use section formula for M and N
The problem states that OM = MN. This implies that M is the midpoint of the segment ON, where O is the origin (0,0). Therefore, if N has coordinates , then M will have coordinates .
Step 4: Substitute M and N into line equations
Since M lies on AB, its coordinates satisfy the equation of line AB. Substituting and into the equation for AB gives us a relationship between and . Since N lies on AC, its coordinates must also satisfy the equation of line AC.
Step 5: Solve for N and then M
Now we have two equations for in terms of . We can equate them to solve for . Once is found, we substitute it back into either equation to find . Finally, we use the relationship to find the coordinates of M.
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