Is it true that x=elog⁡xx=e^{\log x} for all real xx ?

Answer: No, it is not true that x=elog⁡xx=e^{\log x} for all real xx. It is only true for x>0x > 0.

Step-by-step solution

Step 1: Analyze the expression

We need to determine if the given equation x=elog⁡xx = e^{\log x} holds true for all real values of xx. This involves understanding the properties and domains of the exponential and logarithmic functions.

Step 2: Recall the definition of logarithm

The logarithm log⁡x\log x (often written as ln⁡x\ln x in calculus, implying base ee) is defined as the inverse of the exponential function. Specifically, if y=log⁡bxy = \log_b x, then by=xb^y = x. When the base is ee, we have y=ln⁡x  ⟺  ey=xy = \ln x \iff e^y = x.

Step 3: Consider the domain of the logarithm

A crucial aspect of the logarithm function is its domain. The logarithm of a number is only defined for positive real numbers. This means that for log⁡x\log x to be a valid expression, xx must be strictly greater than zero.

Step 4: Evaluate the expression based on the domain

Based on the definition of the logarithm, elog⁡xe^{\log x} is indeed equal to xx, but only for values of xx where log⁡x\log x is defined. This means the equality holds true only for x>0x > 0. It does not hold for all real xx, because log⁡x\log x is undefined for x≤0x \le 0.

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