Let be the largest open interval in which the function is strictly increasing and be the largest open interval in which the function is strictly decreasing. Then is equal to:
Answer: 360
Step-by-step solution
Step 1: Find the derivative of f(x) and determine 'a'
To find where the function is strictly increasing, we need to find its first derivative, , and set it greater than zero. The derivative of is , and the derivative of is . Since is strictly increasing in , for . The critical points occur when . Given that is the largest interval where is strictly increasing, must be a critical point, meaning .
Step 2: Solve for 'a'
Substitute into the derivative and set it equal to zero to solve for the constant . This gives us the value of that makes a critical point.
Step 3: Find the derivative of g(x)
Next, we need to find the derivative of to determine where it is strictly decreasing. We use the product rule for differentiation. Substitute into the expression for before or after differentiation.
Step 4: Simplify g'(x) and find critical points
Factor out common terms from to simplify it. Then substitute into the simplified expression. The critical points are where .
Step 5: Determine the intervals for g(x) decreasing
Substitute into the factored form of and simplify the expression. The critical points are , , and . We need to analyze the sign of in the intervals defined by these critical points. Since , the sign of depends on . is strictly decreasing when . This occurs when and have opposite signs, which is for . Thus, and .
Step 6: Calculate the final value
Finally, substitute the values of , , and into the expression and calculate the result.
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