Let α,β,γ\alpha, \beta, \gamma and δ\delta be the coefficients of x7,x5,x3x^7, x^5, x^3 and xx respectively in the expansion of (x+x3−1)5+(x−x3−1)5,x>1\left(x+\sqrt{x^3-1}\right)^5+\left(x-\sqrt{x^3-1}\right)^5, x>1. If uu and vv satisfy the equations αu+βv=18γu+δv=20\begin{aligned} \alpha u+\beta v &= 18 \\ \gamma u+\delta v &= 20 \end{aligned} then u+vu+v equals:

Answer: 5

Step-by-step solution

Step 1: Simplify the given expression

We use the binomial expansion formula for (A+B)n+(A−B)n(A+B)^n + (A-B)^n. For n=5n=5, the terms with odd powers of BB cancel out. Here, A=xA=x and B=x3−1B=\sqrt{x^3-1}.

Step 2: Substitute A and B into the simplified expression

Substitute A=xA=x and B=x3−1B=\sqrt{x^3-1} into the simplified expression. Then, expand and combine like terms to get the polynomial in descending powers of xx.

Step 3: Identify the coefficients

From the expanded polynomial, we identify the coefficients of x7,x5,x3,x^7, x^5, x^3, and xx. The coefficient of x7x^7 is α\alpha, x5x^5 is β\beta, x3x^3 is γ\gamma, and xx is δ\delta.

Step 4: Substitute coefficients into the given equations

Substitute the values of α,β,γ,\alpha, \beta, \gamma, and δ\delta into the given system of linear equations.

Step 5: Solve the system of equations for u and v

Divide equation (1) by 2 to simplify it to 5u+v=95u+v=9. Divide equation (2) by 10 to simplify it to −2u+v=2-2u+v=2. Subtract the second simplified equation from the first to find uu. Then substitute the value of uu back into one of the simplified equations to find vv.

Step 6: Calculate u+v

Finally, add the calculated values of uu and vv to find their sum.

More from this chapter

All Binomial Theorem solutions →

Solve your own maths question free →