Let MM and mm respectively be the maximum and the minimum values of ∣1+sin⁡2xcos⁡2x4sin⁡4x1+sin⁡2xcos⁡2x4sin⁡4xsin⁡2xcos⁡2x1+4sin⁡4x∣,x∈R\begin{vmatrix} 1 + \sin^2 x & \cos^2 x & 4 \sin 4x \\ 1 + \sin^2 x & \cos^2 x & 4 \sin 4x \\ \sin^2 x & \cos^2 x & 1 + 4 \sin 4x \end{vmatrix}, x \in \mathbf{R}. Then M4−m4M^4 - m^4 is equal to:

Answer: 0

Step-by-step solution

Step 1: Simplify the Determinant

First, let's denote the given determinant as DD. We observe that the first two rows are identical. A fundamental property of determinants states that if two rows (or columns) of a matrix are identical, the determinant of that matrix is zero. However, in this case, the first two rows are not identical. Let's re-examine the problem statement carefully. Ah, I see a typo in the problem statement. Assuming the problem intended for the first two rows to be identical, the determinant would be zero. But if we proceed with the given matrix, we can simplify it using row operations.

Step 2: Apply Row Operations

To simplify the determinant, we can perform row operations. Subtract the first row (R1R_1) from the second row (R2R_2) and also from the third row (R3R_3). This operation does not change the value of the determinant.

Step 3: Evaluate the Determinant

After performing the row operations, the second row becomes all zeros. A property of determinants states that if any row or column of a matrix consists entirely of zeros, then the determinant of the matrix is zero. Therefore, the value of the determinant DD is 00 for all x∈Rx \in \mathbf{R}.

Step 4: Determine Maximum and Minimum Values

Since the determinant DD is always 00, its maximum value MM and minimum value mm are both 00.

Step 5: Calculate M4−m4M^4 - m^4

Finally, we substitute the values of M=0M=0 and m=0m=0 into the expression M4−m4M^4 - m^4 to get the final answer.

More from this chapter

All Determinants solutions →

Solve your own maths question free →