Let N\mathbf{N} be the set of natural numbers. Define a real valued function f:N→Nf: \mathbf{N} \rightarrow \mathbf{N} by f(x)=2x+1f(x)=2 x+1. Using this definition, complete the table given below. x1234567yf(1)=…f(2)=…f(3)=…f(4)=…f(5)=…f(6)=…f(7)=…\begin{array}{|r|c|c|c|c|c|c|c|} \hline x & 1 & 2 & 3 & 4 & 5 & 6 & 7 \\ \hline y & f(1)=\ldots & f(2)=\ldots & f(3)=\ldots & f(4)=\ldots & f(5)=\ldots & f(6)=\ldots & f(7)=\ldots \\ \hline \end{array}

Answer: The completed table is: x1234567yf(1)=3f(2)=5f(3)=7f(4)=9f(5)=11f(6)=13f(7)=15\begin{array}{|r|c|c|c|c|c|c|c|}\hline x & 1 & 2 & 3 & 4 & 5 & 6 & 7 \\ \hline y & f(1)=3 & f(2)=5 & f(3)=7 & f(4)=9 & f(5)=11 & f(6)=13 & f(7)=15 \\ \hline\end{array}

Step-by-step solution

Step 1: Understand the Function Definition

The problem defines a function f(x)=2x+1f(x) = 2x + 1 . This means that for any input value xx , we multiply xx by 2 and then add 1 to get the output value f(x). The domain and codomain are the set of natural numbers N\mathbf{N} .

Step 2: Calculate f(1)

To find f(1)f(1) , we substitute x=1x=1 into the function definition. This gives us 2×1+12 \times 1 + 1 .

Step 3: Calculate f(2)

Next, we find f(2)f(2) by substituting x=2x=2 into the function. This results in 2×2+12 \times 2 + 1 .

Step 4: Calculate f(3)

For f(3)f(3) , we substitute x=3x=3 into the function, yielding 2×3+12 \times 3 + 1 .

Step 5: Calculate f(4), f(5), f(6), f(7)

We continue the process for the remaining values of xx . For x=4x=4 , f(4)=2(4)+1=9f(4) = 2(4)+1 = 9 . For x=5x=5 , f(5)=2(5)+1=11f(5) = 2(5)+1 = 11 . For x=6x=6 , f(6)=2(6)+1=13f(6) = 2(6)+1 = 13 . For x=7x=7 , f(7)=2(7)+1=15f(7) = 2(7)+1 = 15 .

Step 6: Complete the Table

By calculating the function values for each given xx , we can now complete the table.

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