Let A={1,2,3},B={3,4}\mathrm{A}=\{1{,}2{,}3\}, \mathrm{B}=\{3{,}4\} and C={4,5,6}\mathrm{C}=\{4{,}5{,}6\}. Find (i) A×(B∩C)\mathrm{A} \times(\mathrm{B} \cap \mathrm{C}) (ii) (A×B)∩(A×C)(\mathrm{A} \times \mathrm{B}) \cap(\mathrm{A} \times \mathrm{C}) (iii) A×(B∪C)\mathrm{A} \times(\mathrm{B} \cup \mathrm{C}) (iv) (A×B)∪(A×C)(\mathrm{A} \times \mathrm{B}) \cup(\mathrm{A} \times \mathrm{C})

Answer: (i) A×(B∩C)={(1,4),(2,4),(3,4)}\mathrm{A} \times (\mathrm{B} \cap \mathrm{C}) = \{(1{,}4), (2{,}4), (3{,}4)\} (ii) (A×B)∩(A×C)={(1,4),(2,4),(3,4)}(\mathrm{A} \times \mathrm{B}) \cap (\mathrm{A} \times \mathrm{C}) = \{(1{,}4), (2{,}4), (3{,}4)\} (iii) A×(B∪C)={(1,3),(1,4),(1,5),(1,6),(2,3),(2,4),(2,5),(2,6),(3,3),(3,4),(3,5),(3,6)}\mathrm{A} \times (\mathrm{B} \cup \mathrm{C}) = \{(1{,}3), (1{,}4), (1{,}5), (1{,}6), (2{,}3), (2{,}4), (2{,}5), (2{,}6), (3{,}3), (3{,}4), (3{,}5), (3{,}6)\} (iv) (A×B)∪(A×C)={(1,3),(1,4),(1,5),(1,6),(2,3),(2,4),(2,5),(2,6),(3,3),(3,4),(3,5),(3,6)}(\mathrm{A} \times \mathrm{B}) \cup (\mathrm{A} \times \mathrm{C}) = \{(1{,}3), (1{,}4), (1{,}5), (1{,}6), (2{,}3), (2{,}4), (2{,}5), (2{,}6), (3{,}3), (3{,}4), (3{,}5), (3{,}6)\}

Step-by-step solution

Step 1: Calculate B intersection C

First, we find the intersection of sets B and C. The intersection of two sets contains all elements that are common to both sets. In this case, the only common element between B and C is 4.

Step 2: Calculate A cross (B intersection C)

Now we calculate the Cartesian product of set A with the result of the intersection, B∩C\mathrm{B} \cap \mathrm{C}. The Cartesian product of two sets creates ordered pairs where the first element comes from the first set and the second element comes from the second set.

Step 3: Calculate A cross B and A cross C

To find (A×B)∩(A×C)(\mathrm{A} \times \mathrm{B}) \cap (\mathrm{A} \times \mathrm{C}) and (A×B)∪(A×C)(\mathrm{A} \times \mathrm{B}) \cup (\mathrm{A} \times \mathrm{C}), we first need to calculate the Cartesian products A×B\mathrm{A} \times \mathrm{B} and A×C\mathrm{A} \times \mathrm{C}.

Step 4: Calculate (A cross B) intersection (A cross C)

Now we find the intersection of the two Cartesian products A×B\mathrm{A} \times \mathrm{B} and A×C\mathrm{A} \times \mathrm{C}. We look for ordered pairs that are present in both sets.

Step 5: Calculate B union C

For the third part, we first find the union of sets B and C. The union of two sets contains all unique elements from both sets.

Step 6: Calculate A cross (B union C)

Finally, we calculate the Cartesian product of set A with the union of B and C. This involves forming ordered pairs with each element of A and each element of (B∪C)(\mathrm{B} \cup \mathrm{C}).

Step 7: Calculate (A cross B) union (A cross C)

For the last part, we find the union of the two Cartesian products A×B\mathrm{A} \times \mathrm{B} and A×C\mathrm{A} \times \mathrm{C}. This set will contain all unique ordered pairs from both A×B\mathrm{A} \times \mathrm{B} and A×C\mathrm{A} \times \mathrm{C}.

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