Let , and . If is a vector such that , and the angle between and is , then is equal to
Answer: 6
Step-by-step solution
Step 1: Calculate vectors , , and and their magnitudes
First, we calculate the magnitudes of vectors and . Then, we compute the cross product using the determinant formula. Finally, we find the magnitude of vector . These values will be used in subsequent calculations.
Step 2: Determine the magnitude of vector
We use the given condition . Expanding the dot product, we get . Substituting the given and the calculated , we form a quadratic equation in terms of . Solving this equation yields .
Step 3: Calculate
We use the given conditions and the angle between and is to find . We express as a linear combination of , , and a vector perpendicular to both, which is parallel to . By substituting the known dot products and magnitudes, we solve for the scalar coefficient . This yields two possible values for , leading to two possible vectors for and consequently two possible values for .
Step 4: Calculate
We use the formula for the magnitude of the cross product: , where is the angle between and . We substitute the calculated magnitudes of and , and the given angle , to find .
Step 5: Calculate the final expression for both cases
We substitute the two possible values for and the calculated value of into the given expression. In both cases, the result is 6.
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