Let be the solution of the differential equation , such that . Then is equal to:
Answer:
Step-by-step solution
Step 1: Identify the form of the differential equation and find the integrating factor
The given differential equation is of the form of a linear first-order differential equation, which is . Here, and . To solve this, we first need to find the integrating factor (I.F.). The integrating factor is given by the formula .
Step 2: Calculate the integrating factor
We substitute into the integrating factor formula. The integral of is . Therefore, the integrating factor is .
Step 3: Solve the differential equation
The general solution for a linear first-order differential equation is given by . We substitute the expressions for and the integrating factor into this formula. To solve the integral on the right-hand side, we can use a substitution.
Step 4: Evaluate the integral using substitution
Let , so . The integral becomes . We can split this into two integrals and use integration by parts for the term with . After integrating and substituting back , we simplify the expression to find the general solution for .
Step 5: Apply the initial condition to find C
We are given the initial condition . We substitute and into the general solution. Since and , we can solve for the constant .
Step 6: Find
Now that we have the value of , we can write the particular solution. We need to find . We substitute into the particular solution. Since , we can simplify the expression.
Step 7: Calculate the final expression
Finally, we need to calculate the value of . We substitute the value of we just found and simplify the expression.
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