**Quick Drill** 1. Add the following terms. a) 3pq3pq; −2pq-2pq; −5pq-5pq b) −2m2-2m^2; −3mn-3mn; −3m2-3m^2 c) x2yx^2y; −2xy2-2xy^2; −3x2y-3x^2y d) a2bca^2bc; −2ab2c-2ab^2c; −3a2bc-3a^2bc; −4ab2c-4ab^2c 2. Subtract 4x2y−2xy4x^2y - 2xy from xy+yx2xy + yx^2. **Practice 1** 1. Add the following expressions. a) x2+2x+1x^2 + 2x + 1 and x2−5x+4x^2 - 5x + 4 b) x−2xy+y2+7x - 2xy + y^2 + 7 and x2…x^2 \dots c) xz+yx+3x−20xz + yx + 3x - 20 and z−yx+xy+12z - yx + xy + 12 d) xy+yz+zx+5xy + yz + zx + 5 and y…y\dots e) 2x3+3x−22x^3 + 3x - 2, x2−3y+4x^2 - 3y + 4 and y2−xy+2xy^2 - xy + 2x f) 3y4−2y2+123y^4 - 2y^2 + 12, y3−y…y^3 - y\dots

Answer: Quick Drill: 1(a) −4pq-4pq, 1(b) −5m2−3mn-5m^2 - 3mn, 1(c) −2x2y−2xy2-2x^2y - 2xy^2, 1(d) −2a2bc−6ab2c-2a^2bc - 6ab^2c; 2. 3xy−3x2y3xy - 3x^2y. Practice 1: 1(a) 2x2−3x+52x^2 - 3x + 5, 1(c) xz+xy+3x+z−8xz + xy + 3x + z - 8, 1(e) 2x3+x2+5x+y2−3y−xy+22x^3 + x^2 + 5x + y^2 - 3y - xy + 2. (Parts 1(b), 1(d), and 1(f) are truncated in the image).

Step-by-step solution

Step 1: Solve Quick Drill Question 1(a) and 1(b)

To add terms, combine like terms by adding their numerical coefficients. For (a), all three terms share the literal factor pqpq, giving (3−2−5)pq=−4pq(3 - 2 - 5)pq = -4pq. For (b), group the like terms −2m2-2m^2 and −3m2-3m^2 to obtain −5m2-5m^2, leaving the unlike term −3mn-3mn as it is.

Step 2: Solve Quick Drill Question 1(c) and 1(d)

In (c), identify like terms: x2yx^2y and −3x2y-3x^2y combine to −2x2y-2x^2y, while −2xy2-2xy^2 is an unlike term because the exponents on xx and yy differ. In (d), group a2bca^2bc with −3a2bc-3a^2bc to get −2a2bc-2a^2bc, and group −2ab2c-2ab^2c with −4ab2c-4ab^2c to get −6ab2c-6ab^2c.

Step 3: Solve Quick Drill Question 2

Subtracting an expression means adding its additive inverse, so change the sign of every term in (4x2y−2xy)(4x^2y - 2xy). Note that yx2yx^2 is identical to x2yx^2y by the commutative property of multiplication. Combining like terms yields 3xy−3x2y3xy - 3x^2y.

Step 4: Solve Practice 1 Question 1(a)

Group like terms corresponding to x2x^2, xx, and the constant terms together. Adding the coefficients gives 1+1=21 + 1 = 2 for x2x^2, 2−5=−32 - 5 = -3 for xx, and 1+4=51 + 4 = 5 for the constants.

Step 5: Solve Practice 1 Question 1(c)

Since multiplication is commutative, yx=xyyx = xy. Thus, the terms yx−yx+xyyx - yx + xy simplify to xyxy. Combining the constants gives −20+12=−8-20 + 12 = -8, while the remaining terms xzxz, 3x3x, and zz have no other like terms.

Step 6: Solve Practice 1 Question 1(e)

Collect like terms across the three expressions. The like linear terms in xx are 3x+2x=5x3x + 2x = 5x, and the constants are −2+4=2-2 + 4 = 2. Arranging the remaining terms gives 2x3+x2+5x+y2−3y−xy+22x^3 + x^2 + 5x + y^2 - 3y - xy + 2.

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