**Quick Drill**
1. Add the following terms.
a) 3pq; −2pq; −5pq
b) −2m2; −3mn; −3m2
c) x2y; −2xy2; −3x2y
d) a2bc; −2ab2c; −3a2bc; −4ab2c
2. Subtract 4x2y−2xy from xy+yx2.
**Practice 1**
1. Add the following expressions.
a) x2+2x+1 and x2−5x+4
b) x−2xy+y2+7 and x2…
c) xz+yx+3x−20 and z−yx+xy+12
d) xy+yz+zx+5 and y…
e) 2x3+3x−2, x2−3y+4 and y2−xy+2x
f) 3y4−2y2+12, y3−y…
Answer: Quick Drill: 1(a) −4pq, 1(b) −5m2−3mn, 1(c) −2x2y−2xy2, 1(d) −2a2bc−6ab2c; 2. 3xy−3x2y. Practice 1: 1(a) 2x2−3x+5, 1(c) xz+xy+3x+z−8, 1(e) 2x3+x2+5x+y2−3y−xy+2. (Parts 1(b), 1(d), and 1(f) are truncated in the image).
Step-by-step solution
Step 1: Solve Quick Drill Question 1(a) and 1(b)
To add terms, combine like terms by adding their numerical coefficients. For (a), all three terms share the literal factor pq, giving (3−2−5)pq=−4pq. For (b), group the like terms −2m2 and −3m2 to obtain −5m2, leaving the unlike term −3mn as it is.
Step 2: Solve Quick Drill Question 1(c) and 1(d)
In (c), identify like terms: x2y and −3x2y combine to −2x2y, while −2xy2 is an unlike term because the exponents on x and y differ. In (d), group a2bc with −3a2bc to get −2a2bc, and group −2ab2c with −4ab2c to get −6ab2c.
Step 3: Solve Quick Drill Question 2
Subtracting an expression means adding its additive inverse, so change the sign of every term in (4x2y−2xy). Note that yx2 is identical to x2y by the commutative property of multiplication. Combining like terms yields 3xy−3x2y.
Step 4: Solve Practice 1 Question 1(a)
Group like terms corresponding to x2, x, and the constant terms together. Adding the coefficients gives 1+1=2 for x2, 2−5=−3 for x, and 1+4=5 for the constants.
Step 5: Solve Practice 1 Question 1(c)
Since multiplication is commutative, yx=xy. Thus, the terms yx−yx+xy simplify to xy. Combining the constants gives −20+12=−8, while the remaining terms xz, 3x, and z have no other like terms.
Step 6: Solve Practice 1 Question 1(e)
Collect like terms across the three expressions. The like linear terms in x are 3x+2x=5x, and the constants are −2+4=2. Arranging the remaining terms gives 2x3+x2+5x+y2−3y−xy+2.