Adding the additional time to Sheldon's time gives Missy's time as (x + (1)/(20)) minutes, or (x + (3)/(60)) minutes. Alternatively, in seconds, Sheldon takes 60x seconds, so Missy takes (60x + 3) seconds.

Adding the additional time to Sheldon's time gives Missy's time as (x + (1)/(20)) minutes, or (x + (3)/(60)) minutes. Alternatively, in seconds, Sheldon takes 60x seconds, so Missy takes (60x + 3) seconds.

Sheldon takes x minutes to solve a Math problem, while Missy takes 3 more seconds than Sheldon. Which of the following shows the time taken by Missy?

Answer: $\left(x + \frac{1}{20}\right)$ minutes (or $60x + 3$ seconds)

Step-by-step solution

Step 1: Express the given times

We are given that Sheldon takes $x$ minutes to solve the problem. Missy takes $3$ more seconds than Sheldon.

Step 2: Convert seconds to minutes

Since Sheldon's time is given in minutes and the extra time taken by Missy is in seconds, we can express the quantities in the same unit. There are $60$ seconds in $1$ minute, so $3$ seconds is equal to $\frac{3}{60}$ minutes, which simplifies to $\frac{1}{20}$ minutes.

Step 3: Find the total time taken by Missy

Adding the additional time to Sheldon's time gives Missy's time as $\left(x + \frac{1}{20}\right)$ minutes, or $\left(x + \frac{3}{60}\right)$ minutes. Alternatively, in seconds, Sheldon takes $60x$ seconds, so Missy takes $(60x + 3)$ seconds.

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