Show that and are consecutive terms of an A.P., if and are in A.P.
Answer: The given terms and are consecutive terms of an A.P.
Step-by-step solution
Step 1: Understand the condition for A.P.
For three terms to be in an Arithmetic Progression (A.P.), the middle term must be the average of the other two terms. This means that the difference between the second and first term is equal to the difference between the third and second term. So, if are in A.P., then , which simplifies to .
Step 2: Define the terms to be checked
We are given three expressions and need to show that they form an A.P. Let's label these expressions as , , and for clarity. We need to prove that .
Step 3: Calculate
First, we calculate the sum of the first and third terms, . We combine like terms to simplify the expression.
Step 4: Substitute into
From the condition that are in A.P., we know . We substitute this into the expression for to simplify it further. This substitution helps us relate the expression to the middle term .
Step 5: Calculate
Next, we calculate two times the middle term, . This is the expression we need to show is equal to .
Step 6: Substitute into
We substitute into the expression for . We can rewrite as part of . This allows us to express in terms of , , and .
Step 7: Compare and
We have and . These expressions do not immediately look equal. Let's re-evaluate the substitution in more carefully.
Step 8: Re-evaluate using
Let's re-substitute into the expression for . We group the terms involving and to make the substitution clearer. This leads to .
Step 9: Conclusion
Since we have shown that and , it follows that . This proves that the given terms are in an A.P.
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