**Simple Interest** * P→PrincipalP \rightarrow \text{Principal} * R→RateR \rightarrow \text{Rate} * T→TimeT \rightarrow \text{Time} SI=P×R×T100\text{SI} = \frac{P \times R \times T}{100} A=P+SIA = P + \text{SI} **Example** * P=₹10,000P = \text{₹}10{,}000 * R=10%R = 10\% * T=2 yearsT = 2\text{ years} * SI=₹2,000\text{SI} = \text{₹}2{,}000 * Amount=₹12,000\text{Amount} = \text{₹}12{,}000 **Calculation:** Given: P=₹10,000P = \text{₹}10{,}000, R=10%R = 10\%, T=2 yearsT = 2\text{ years} SI=10,000×10×2100\text{SI} = \frac{10{,}000 \times 10 \times 2}{100} SI=1,000×2\text{SI} = 1{,}000 \times 2 SI=₹2,000\text{SI} = \text{₹}2{,}000 **Calculating Amount:** A=10,000+2,000A = 10{,}000 + 2{,}000 A=₹12,000A = \text{₹}12{,}000

Answer: Simple Interest = ₹2,000 and Amount = ₹12,000

Step-by-step solution

Step 1: State given values and formulas

We identify the given parameters from the problem: the principal PP is 1000010000 rupees, the rate of interest RR is 10%10\%, and the time period TT is 22 years. The standard formula for simple interest is SI=P×R×T100\text{SI} = \frac{P \times R \times T}{100}.

Step 2: Calculate Simple Interest

Substitute P=10000P = 10000, R=10R = 10, and T=2T = 2 into the simple interest formula. Simplifying the fraction by dividing the numerator and denominator by 100100 gives 1000×2=20001000 \times 2 = 2000. Thus, the simple interest is ₹2000\text{₹}2000.

Step 3: Calculate Total Amount

The total amount AA is the sum of the principal PP and the simple interest SI\text{SI}. Substituting P=10000P = 10000 and SI=2000\text{SI} = 2000, we get A=10000+2000=12000A = 10000 + 2000 = 12000 rupees.

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